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| CANopen Network Interface | |||||
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Example | The following illustration shows the calculation of the length of a cable located | ||||||||||||
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2
3
4
1m (3 ft)
1 m | 3 m |
(3 ft) | (10 ft) |
ΣL=5 m (16 ft)
1m (3 ft)
3 m | 3 m |
(10 ft) | (10 ft) |
ΣL=7 m (23 ft)
Min interval > 0.6 * 7 m (23 ft)
Min interval > 4.2 m (13.8 ft)
The table below describes the components of a CANopen network:
Number | Description |
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1 | Connected CANopen devices |
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2 | Drop cables (tap junction box / device) |
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3 | Tap junction boxes |
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4 | Connection cables (tap junction box / tap junction box) |
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In this example, we have two tap junction boxes and 6 devices. We start by calculating the sum of the lengths of cables for each tap junction box, and we obtain
5m (16 ft) and 7 m (23 ft). We keep the longest length, i.e. 7 m (23 ft). The minimum length of the cable between the two tap junction boxes is equal to 60% of 7 m, i.e. 4.2 m (13.8 ft).
| Number of | In addition to the length limitations over the whole of the CANopen bus, the following | |
| Connected | limitations apply: |
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| Devices | Whatever the case, no more than 64 devices may be connected on the same |
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1606218 02 08/2006 |
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