CANopen Network Interface

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Example

The following illustration shows the calculation of the length of a cable located

 

between two tap junction boxes.

 

1

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

2

3

4

1m (3 ft)

1 m

3 m

(3 ft)

(10 ft)

ΣL=5 m (16 ft)

1m (3 ft)

3 m

3 m

(10 ft)

(10 ft)

ΣL=7 m (23 ft)

Min interval > 0.6 * 7 m (23 ft)

Min interval > 4.2 m (13.8 ft)

The table below describes the components of a CANopen network:

Number

Description

 

 

1

Connected CANopen devices

 

 

2

Drop cables (tap junction box / device)

 

 

3

Tap junction boxes

 

 

4

Connection cables (tap junction box / tap junction box)

 

 

In this example, we have two tap junction boxes and 6 devices. We start by calculating the sum of the lengths of cables for each tap junction box, and we obtain

5m (16 ft) and 7 m (23 ft). We keep the longest length, i.e. 7 m (23 ft). The minimum length of the cable between the two tap junction boxes is equal to 60% of 7 m, i.e. 4.2 m (13.8 ft).

 

Number of

In addition to the length limitations over the whole of the CANopen bus, the following

 

Connected

limitations apply:

 

 

Devices

Whatever the case, no more than 64 devices may be connected on the same

 

 

 

 

 

segment.

 

 

 

￿

 

1606218 02 08/2006

 

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Image 41
Schneider Electric IP67 Example, Min interval 0.6 * 7 m 23 ft Min interval 4.2 m 13.8 ft, Number, Connected, Devices