Honeywell UDC 3300 manual Summary of Flow Values At Values Conditions, Flow Sfcm

Figure 4-1 Example of Mass Flow Compensation using Multiplier/Divider Algorithm, continued

Example - Mass Flow Compensation

Determined value of K:
K 2 =	1	x	Tref	=	600		= 0.14914
					(90) (44.7)
90			Pref
Therefore K = 0.386
Q SCFM = (0.386) (650)						DPf (in H2O) (IN3 + 14.7)
							(IN2 + 460)

K

(Calc HI - Calc LO )

Summary of Flow Values At Values Conditions

Reference Conditions

Temp (Tf )		Pressure (Tf )	Flow (SFCM)
			DPf = 45" H 2O (50%)	DPf	= 90" H2 O (100%)
	( R)	(psia)
140	F + 460	30 psi + 14.7	459		650
170	F + 460	50 psi + 14.7	539		763
170	F + 460	20 psi + 14.7	395		559
110	F + 460	50 psi + 14.7	567		802
110	F + 460	20 psi + 14.7	415		587

22050

4/00 UDC 3300 Process Controller Product Manual 103