IP Addressing

1 Networking Overview

Example

To continue the example using a 3-bit subnet ID, assume a Class C network ID of 192.168.50.xxx. This network ID can provide 254 usable IP addresses, all on the same network — from 192.168.50.1 to 192.168.50.254. If we divide this network into 3-bit subnets, we will have 6 usable subnets with 30 usable IP addresses in each subnet. Note that we have lost 74 usable IP addresses in the process because we had to discard the all-ones and all-zeros subnet IDs (62 addresses) and host IDs (12 addresses). There is always a loss of usable IP addresses with subnetting.

The following table shows the subnet boundaries for the six subnets formed with 3 bits. The boundaries are the numbers formed by using all combinations of 3 bits as the highest-order bits in an octet (Columns 1 and 2) and then using these numbers in the 4th octet for the host IDs.

Binary

Decimal

Range of usable IP

Subnet

Subnet

Addresses in the

Boundaries

Boundaries

Subnet

(for 3 bits)

 

 

 

 

 

00000000

0

not usable

00100000

32

192.168.50.33 to

 

 

192.168.50.62

 

 

 

01000000

64

192.168.50.65 to

 

 

192.168.50.94

 

 

 

01100000

96

192.168.50.97 to

 

 

192.168.50.126

 

 

 

10000000

128

192.168.50.129 to

 

 

192.168.50.158

 

 

 

10100000

160

192.168.50.161 to

 

 

192.168.50.190

 

 

 

11000000

192

192.168.50.193 to

 

 

192.168.50.222

 

 

 

11100000

224

not usable

 

 

 

For example, the IP addresses 192.168.50.75 and 192.168.50.91 are on the same subnet but 192.168.50.100 is on a different subnet. This is illustrated in the following diagram where the subnet mask, 255.255.255.244 is used to compare the first 27 binary digits or each address.

Administration for Network Connectivity

 

 

555-233-504 — Issue 1 — April 2000

CID: 77730

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Lucent Technologies Release 8.2 manual Example